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Question

If P is any point on the median AD of a ΔABC, then ar ABPar ACP= _________.

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Solution

Given: P is any point on the median AD of a ΔABC

We know, median of a triangle divides it into two triangles of equal area.

Therefore, ar (ΔADB) = ar (ΔADC) ...(1)
Also, ar (ΔPDB) = ar (ΔPDC) ...(2)

Subtracting (2) from (1), we get
ar (ΔADB) − ar (ΔPDB) = ar (ΔADC) − ar (ΔPDC)
⇒ ar (ΔABP) = ar (ΔACP)
ar ABPar ACP= 1


Hence, ar ABPar ACP= 1.

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