If P is pressure, ρ is the density then Pρ has the same dimensions of :
A
Force per unit mass
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B
Energy per unit mass
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C
Power per unit velocity
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D
Relative density
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Solution
The correct option is B Energy per unit mass P=pressure=ForceArea=M1L1T−2L2=[M1L−1T−2] ρ=[M1L−3T0]
Pρ=M1L−1T−2M1L−3=[M0L2T−2]
Force per unit mass =M1L1T−2M1=[L1T−2] Energy per unit mass =M1L2T−2M1=[L2T−2] Power per unit velocity =M1L2T−3LT1=[M1L1T−2] Relative density =[M0L0T0]