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Question

If p is selected from the set {1,2,3,......100}, then the probability of selecting p such that the number 2p+3p+5p is divisible by 4 is 


Solution

For p=1
2+3+5=10 which is not divisible by 4.
For p2
2p+(41)p+(4+1)p=(1)p+(1)p+4n ; nI
So this will be divisible when p is odd except 1
Required number of  p is 49
Total possible values of  p is100
P(e)=49100=0.49

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