If P is the interoir point of parallelogram ABCD, prove that the sum of area of ΔPAB and ΔPDC is as equal to half of the area of parallelogram ABCD [2 MARKS]
Concept : 1 Mark
Proof : 1 Mark
Draw a line QR parallel to AB and passing through P.
Area of triangle ABP = 12 Area of AQRB
Area of triangle DPC = 12 Area of DQRC
So sum of their areas = 12 Area of AQRB+ 12 Area of DQRC
= 12 Area of parallelogram ABCD