If p is the perpendicular from origin to the line xa+yb=1, then
A
1p2=1a2+1b2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
1p2=1a2−1b2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1p2=−1a2−1b2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1p2=−1a2+1b2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A1p2=1a2+1b2 Given line is xa+yb=1 Thus, the length of perpendicular from origin to the line xa+yb=1 is p=b×0+a×0−ab√b2+a2 According to question, ⇒−ab√b2+a2=p ⇒(ab)2b2+a2=p2 ⇒1p2=1a2+1b2.