If P is the set of all Irrational Numbers, Q is the set of all Rational Numbers, Z is the set of all Integers,
then which of the following is correct?
A
Z⊂Q;Z⊄P.
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B
Q⊂Z
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C
Z⊂P;Z⊂Q
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Solution
The correct option is AZ⊂Q;Z⊄P. Z is the set of all Integers, Q is the set of all Rational Numbers, P is the set of all Irrational Numbers, R is the set of all Real Numbers
We know the order, i.e., Z⊂Q⊂R;P⊂R.