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Question

If P(A)=12,P(B)=13,P(C)=12and P(AB)=P(BC)=P(CA)=14and P(ABC)=18 then find P(ABC).

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Solution

Given, P(A)=12,P(B)=13,P(C)=12and P(AB)=P(BC)=P(CA)=14and

P(ABC)=18.......(1)

Now, we have,

P(ABC)

=P(A)+P(B)+P(C)P(AB)P(BC)P(AC)+P(ABC)

=12+13+123×14+18

=1+1334+18

=1+1358

=1724

=1724.

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