Question

If $P\left(A\right)=\frac{1}{2}$, $P\left(B\right)=0$, then $P\left(A|B\right)$ is

• A. $0$
• B. $\frac{1}{2}$
• C. Not defined
• D. $1$

Answer 1

The correct option is C Not defined

It is given that, $P\left(A\right)=\frac{1}{2}$ and $P\left(B\right)=0$
$P\left(A|B\right)=\frac{P(A\cap B)}{P\left(B\right)}=\frac{P(A\cap B)}{0}$
Therefore, $P\left(A|B\right)$ is not defined.
Thus, the correct answer is (C).