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Question

If P={x:x<3,xN},Q={x:x2,xW}, then (PQ)×(PQ) is

A
{(0,1),(0,2),(1,1),(1,2),(2,1),(2,2)}
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B
{(0,1),(0,2),(0,3),(1,1),(1,2), (1,3),(2,1),(2,2),(2,3)}
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C
ϕ
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D
{(0,1),(0,2),(0,3)}
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Solution

The correct option is A {(0,1),(0,2),(1,1),(1,2),(2,1),(2,2)}
P={1,2},Q={0,1,2}PQ={1,2},PQ={0,1,2}
(PQ)×(PQ)={(0,1),(0,2),(1,1),(1,2),(2,1),(2,2)}

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