If P (n) is the statement "2" ≤ "3n", and If P (r) is true, prove that P (r + 1) is true.
p(n):2n≤3n
Given that P(r) is true
⇒2r≤3r
Multiplying both the sides by 2.
2.2r≤2.3r
22+1≤6r
≤3r+3r
≤3+3r.
[Since 3r≤3⇒3r+3r≤3+3r]
2r+1≤3(r+1)
⇒ P(r + 1) is true.