If P(n, n) denotes the number of permutations of n different things taken all at a time then P(n, n) is also identical to

n.P(n 1, n 1)

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P(n, n 1)

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(n r) . P(n, r)

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Solution

The correct option is D n!
$P (n, n) = \frac{n!}{0!} = n!$
No one correct, answer is $n .$

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