If (p∧~r)→(~p∨q) is false, then the truth values of p, q, and r are respectively
T, F and F
F, F and T
F, T and T
T, F and T
Explanation for Correct option
Since (p∧~r)→(~p∨q)≡F
⇒(p∧~r)≡T&(~p∨q)≡F
⇒P≡T,~r≡Tand~p≡F,q≡F
⇒p≡T,q≡F,r≡F
∴ p is true, r is false and q is false.
Hence Option (A) is correct.
If p⇒(q∨r) is false, then the truth values of p,q,r are respectively