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Question

If P, Q, and R be three points on a parabola whose ordinates are in geometrical progression, prove that the tangents at P and R meet on the ordinate of Q.

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Solution

P(at21,2at1),Q(at22,2at2),R(at23,2at3)
given (2at2)2=(2at1)(2at3)
t22=t1t3t2=t1t3
So Q is (at1t3,2at1t3).......(i)
Equation of tangent at P is
t1y=x+at21
Equation of tangent at R is
t3y=x+at23
Point of intersection of tangents is (at1t3,a(t1+t3))
It also lies on the parabola
(a(t1+t3))2=4a(at1t3)t1+t3=2t1t3a(t1+t3)=2at1t3
The ordinate of Q obtained in (i) is also same
Hence proved.

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