Question

If $p,q$ are the roots of equation $x^2+px+q=0$, then the value of $p$ must be equal to

• A. $0,1$
• B. $1$
• C. $2$
• D. $1,-2$

Answer 1

The correct option is A $0,1$

Given equation
$x^2+px+q$
Also, given $p,q$ are the roots of the equation.
$p+q=-p$
$2p=-q$ .....$\left(1\right)$
And $pq=q$
$q(p-1)=0$
$\Rightarrow q=0$ or $p=1$
So, by $\left(1\right)$, $q=0\Rightarrow p=0$
Hence, the values of $p$ are $0,1$.