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Question

If p, q are the roots of the equation x23x+2=0 , find the equation which has roots as (2p + 1) and (2q + 1).

A
x2 – 8x + 12 = 0
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B
2x2 – 8x + 15 =0
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C
2x2 – 7x + 14 = 0
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D
x2 – 8x + 15 = 0
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Solution

The correct option is D x2 – 8x + 15 = 0

Given equation: x23x+2=0
with roots p, q

When the roots become 2p and 2q,
the equation becomes:
(x2)23(x2)+2=0,x26x+8=0

When the roots become
(2p+1) & (2q+1)
the equation becomes:

(x1)26(x1)+8=0,x28x+15=0.
Hence option (D)


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