If p, q are the roots of the equation x2−3x+2=0 , find the equation which has roots as (2p + 1) and (2q + 1).
Given equation: x2−3x+2=0
with roots p, q
When the roots become 2p and 2q,
the equation becomes:
(x2)2−3(x2)+2=0,x2−6x+8=0
When the roots become
(2p+1) & (2q+1)
the equation becomes:
(x−1)2−6(x−1)+8=0,x2−8x+15=0.
Hence option (D)