If p,q,r are positive integers, and Δ=12∣∣
∣∣pC1pC2pC3qC1qC2qC3rC1rC2rC3∣∣
∣∣ then
A
Δ is an even integer
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B
Δ is divisible by 12
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C
Δ is an rational number
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D
None of these
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Solution
The correct options are AΔ is an even integer DΔ is an rational number We have pC1=p,pC2=12p(p−1)andpC3=16p(p−1)(p−2) Thus, Δ=pqr∣∣
∣
∣∣1p−1(p−1)(p−2)1q−1(q−1)(q−2)1r−1(r−1)(r−2)∣∣
∣
∣∣ Using R3→R3−R2andR2→R2−R1 we get Δ=pqr∣∣
∣
∣∣1p−1(p−1)(p−2)0q−p(q−p)(q+p−3)0r−q(r−q)(r+q−3)∣∣
∣
∣∣ =pqr(q−p)(r−q)∣∣∣1q+p−31r+q−3∣∣∣ =pqr(q−p)(r−q)(r−p) Now, use at least one of these six factors is even.