If p,q & r are the zeroes of a cubic polynomial $a x^{3} + b x^{2} + c x + d$ , then what will be p+q+r?

- \frac{b}{a}

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- \frac{c}{a}

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\frac{b}{a}

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\frac{c}{a}

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Solution

The correct option is A $- \frac{b}{a}$
We know that for a cubic polynomial $a x^{3} + b x^{2} + c x + d$
Sum of zeroes = $- \frac{b}{a}$
Therefore, $p + q + r = - \frac{b}{a}$

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