If P,Q,R are three points on a parabola y2=4ax whose ordinates are in geometric progression, then tangents at P and R meet on the
A
tangent at vertex of parabola
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B
abscissa of Q
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C
directrix of parabola
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D
ordinate of Q
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Solution
The correct option is B abscissa of Q Let the co-ordinates of P,Q,R be (ati2,2ati);i=1,2,3 having co-ordinates in G.P. So that t1,t2,t3 are also in G.P. i.e., t1t3=t22
Equations of the tangent at P and R are
t1y=x+at12 and t3y=x+at32 which intersects at the point
x+at12t1=x+at32t3 ⇒x=at1t3=at22 which is a line through Q parallel to Y−axis.