If (p+q)th term of G.P. is m and (p-q)th term is n, then pth term will be

(\frac{m}{n})

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(m - n)

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m n

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\sqrt{m n}

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Solution

The correct option is D $\sqrt{m n}$
$T_{p + q} = a r^{p + q - 1} = m . . . . . . . . . . . . . . . . . . . . (1) T_{p - q} = a r^{p - q - 1} = n . . . . . . . . . . . . . . . . . . . . . . . (2) T_{p} = a r^{p - 1} . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . (3)$
Multiplying (1) and (2)
$a^{2} r^{2 p - 2} = m n \Rightarrow T_{p} = a r^{p - 1} = \sqrt{m n}$

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Similar questions

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