If $p$ satisfies the equation
$(3 p^{2} + 14 p + 24) - 2 (p^{2} + 7 p + 20) = 0$ , what is one possible value of $3 p + 6$ ?

20

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18

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12

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10

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Solution

The correct option is A $18$
Given, $(3 p^{2} + 14 p + 24) - 2 (p^{2} + 7 p + 20) = 0$
$\Rightarrow 3 p^{2} + 14 p + 24 - 2 p^{2} - 14 p - 40 = 0$
$\Rightarrow p^{2} - 16 = 0$
$\Rightarrow p^{2} = 16$
$\Rightarrow p = \sqrt{16}$
$\Rightarrow p = 4$
$∴ 3 p + 6 = (3 \times 4) + 6 = 12 + 6 = 18$

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If p satisfies the equation(3p2+14p+24)−2(p2+7p+20)=0, what is one possible value of 3p+6?

The correct option is A 18Given, (3p2+14p+24)−2(p2+7p+20)=0⇒3p2+14p+24−2p2−14p−40=0⇒p2−16=0⇒p2=16⇒p=√16⇒p=4∴3p+6=(3×4)+6=12+6=18

If $p$ satisfies the equation
$(3 p^{2} + 14 p + 24) - 2 (p^{2} + 7 p + 20) = 0$ , what is one possible value of $3 p + 6$ ?

The correct option is A $18$
Given, $(3 p^{2} + 14 p + 24) - 2 (p^{2} + 7 p + 20) = 0$
$\Rightarrow 3 p^{2} + 14 p + 24 - 2 p^{2} - 14 p - 40 = 0$
$\Rightarrow p^{2} - 16 = 0$
$\Rightarrow p^{2} = 16$
$\Rightarrow p = \sqrt{16}$
$\Rightarrow p = 4$
$∴ 3 p + 6 = (3 \times 4) + 6 = 12 + 6 = 18$