Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
316≤p≤14
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
14≤p≤1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A34≤p≤1 Given, p=sin2x+cos4x =sin2x+cos2x(1−sin2x) =(sin2x+cos2x)−sin2xcos2x =1−sin2xcos2x≤1....(i) Again, p=1−cos2x+cos4x =(cos2x−12)2+34 ⇒p≥34....(ii) ∴ From Eqs. (i) and (ii), we get 34≤p≤1.