If p -1- what is the value of 1- p 20 - A- 1- pB- 1024C- -1024D- -p

The correct option is C 1024Given, p=√( 1) so, p^2=( 1) therefore, (1 p)^20 = ((1 p)^2)^10 =((1^2+p^2+2p)^10), putting the value of p^2, we get =((2p)^10) =(2 ...

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Byju's Answer

Standard VIII

Mathematics

Finding Square Root of a Number

If p =√-1, wh...

Question

If $p = \sqrt{- 1}$ , what is the value of $(1 - p)^{20}$ ?

-p

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-1024

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1024

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1-p

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Solution

The correct option is B -1024
Given, $p = \sqrt{- 1}$
so, $p^{2} = (- 1)$
therefore, $(1 - p)^{20} = ((1 - p)^{2})^{10}$
$= ((1^{2} + p^{2} - 2 p)^{10})$ ,
putting the value of $p^{2}$ , we get
$= ((- 2 p)^{10})$
$= (- 2^{10} \times p^{10})$
$= 1024 \times (- 1)^{5}$ , putting the value of $p^{2}$
$= - 1024$

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If p=√−1, what is the value of (1−p)20?

The correct option is B -1024Given, p=√−1 so, p2=(−1) therefore, (1−p)20=((1−p)2)10 =((12+p2−2p)10), putting the value of p2, we get =((−2p)10) =(−210×p10) =1024×(−1)5 , putting the value of p2 =−1024

If $p = \sqrt{- 1}$ , what is the value of $(1 - p)^{20}$ ?