If $p (t) = t^{3} - 1$ , find the values of $p (1), p (- 2) .$

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Solution

Given: $p (t) = t^{3} - 1$
$p (1) = 1^{3} - 1$
$= 1 - 1 = 0$

$p (- 2) = (- 2)^{3} - 1$
$= - 8 - 1 = - 9$

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