Question 69
If P = -(x - 2), Q = -2(y + 1) and R = -x + 2y, find a, when P+Q+R = ax.
Given, P = -(x - 2), Q = -2(y + 1) and R = -x + 2y
Also given, P + Q + R = ax
On putting the values of P, Q and R on LHS, we get
-(x - 2) + [-2(y + 1)] + (-x + 2y) = ax
⇒−x+2+(−2y−2)−x+2y=ax
⇒−x+2−2y−2−x+2y=ax
On combining the like terms,
- x - x -2y + 2y + 2 - 2 = ax
⇒−2x=ax
By comparing LHS and RHS, we get a = -2