If $p (x) = 2 x^{3} - 3 x^{2} + 4 x - 2$ , then $p (- 1)$ is :

-2

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-11

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Solution

The correct option is B -11
$p (x) = 2 x^{3} - 3 x^{2} + 4 x - 2$
Put $x = - 1$
So, $p (- 1) = 2 (- 1)^{3} - 3 (- 1)^{2} + 4 (- 1) - 2$
or, $p (- 1) = - 2 - 3 - 4 - 2 = - 11$
So, option $B$ is correct.

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