If $p (x) = 2 x^{3} - 3 x^{2} + 4 x - 5$ . Find the remainder when $p (x)$ is divided by ,
$x - 1$

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Solution

The correct option is D -2
$p (x) = 2 x^{3} - 3 x^{2} + 4 x - 5$

$g (x) = x - 1$
Put, $x - 1 = 0$
$⟹ x = 1$

Thus putting $x = 1$ in $p (x)$
$p (1) = 2 (1)^{3} - 3 (1)^{2} + 4 (1) - 5$
$= 2 - 3 + 4 - 5$
$= - 2$
Therefore,
Remainder $= - 2$

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If p(x)=2x3−3x2+4x−5. Find the remainder when p(x) is divided by , x−1

The correct option is D -2p(x)=2x3−3x2+4x−5 g(x)=x−1 Put, x−1=0 ⟹x=1Thus putting x=1 in p(x)p(1)=2(1)3−3(1)2+4(1)−5 =2−3+4−5 =−2Therefore,Remainder =−2

If $p (x) = 2 x^{3} - 3 x^{2} + 4 x - 5$ . Find the remainder when $p (x)$ is divided by ,
$x - 1$

The correct option is D -2
$p (x) = 2 x^{3} - 3 x^{2} + 4 x - 5$

$g (x) = x - 1$
Put, $x - 1 = 0$
$⟹ x = 1$

Thus putting $x = 1$ in $p (x)$
$p (1) = 2 (1)^{3} - 3 (1)^{2} + 4 (1) - 5$
$= 2 - 3 + 4 - 5$
$= - 2$
Therefore,
Remainder $= - 2$