If $p (x) = 2 x^{3} - 3 x^{2} + 4 x - 5$ . Find the remainder when $p (x)$ is divided by ,

$x + 3$

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-98

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-106

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Solution

The correct option is B -98
$p (x) = 2 x^{3} - 3 x^{2} + 4 x - 5$

$g (x) = x + 3$
$=> x + 3 = 0$
$=> x = - 3$
Thus by putting x=-3 in p(x) we get,
$p (- 3) = 2 (- 3)^{3} - 3 (- 3)^{2} + 4 (- 3) - 5$
$= - 54 - 27 - 12 - 5$
$= - 98$
Therefore,
Remainder= $- 98$

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