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Question

If p(x)=2x3+5x23x2 is divided by x1, then find the remainder.

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Solution

Given, polynomial, p(x)=2x3+5x23x2 divided by (x1).

The polynomial is divided by (x1) .
Then put(x1)=0 x=1
we get,
p(1)= 2(1)3+5(1)23(1)2
p(1)=2+532
p(1)=2+55
p(1)=2.

So, when p(x)= 2x3+5x23x2 is divided by x1, the remainder obtained is 2.

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