Question

If $P\left(x\right)=3\times x^2-3(a-1)x-1=0$ has one of the zeroes as 1. Find the value of a.

Answer 1

Given 1 ie Zero of polynomial
P (1) = 0
$P\left(1\right)=3\times 1-3(a-1)1-1=0$
$=3-3a+1-1=0$
$\Rightarrow 3-3a=0$
$3=3a$
$a=\frac{3}{3}=1$