If px-x15- x-1-2-3-4-5-0 otherwise- then px-1 or 2 is

The correct option is A 115 #10; #10;[ #10;P(x)=x/15, x=1,2,3,4,5; ...

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Standard XII

Mathematics

Theorems for Continuity

If px=x15, ...

Question

If $p (x) = \frac{x}{15}, x = 1, 2, 3, 4, 5 = 0$ otherwise, then $p (x = 1 o r 2)$ is

\frac{1}{15}

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\frac{2}{15}

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\frac{1}{5}

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N o n e o f t h e s e

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Solution

The correct option is A $\frac{1}{15}$
$\begin{matrix} P (x) = \frac{x}{15}, x = 1, 2, 3, 4, 5 = 0 other wise \begin{matrix} p (x = 1 or 2) & = p (x = 1) + p (x = 2) = \frac{1}{15} + \frac{2}{15} = \frac{1}{5} \end{matrix} \end{matrix}$

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Similar questions

Q. If the quadratic equation

p x^{2} - 2 \sqrt{5} p x + 15 = 0

,has two roots then find the value of p.

Q. If the quadratic equation

p x^{2} - 2 \sqrt{5} p x + 15 = 0

has two equal roots then find the value of

p

If $- 5$ is a root of the quadratic equation $2 x^{2} + p x - 15 = 0$ and the quadratic equation $p (x^{2} + x) + k = 0$ has equal roots, find the value of $k$ .

If -5 is a root of quadratic equation 2x^2+px-15=0 and the quadratic equation p(x^2+x)+k=0 has equal roots find the value of k

Q. Question 15
Check whether p(x) is a multiple of g(x) or not:

(i)

p (x) = x^{3} - 5 x^{2} + 4 x - 3, g (x) = x - 2

(ii)

p (x) = 2 x^{3} - 11 x^{2} - 4 x + 5, g (x) = 2 x + 1

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If p(x)=x15,x=1,2,3,4,5=0 otherwise, then p(x=1 or 2) is

The correct option is A 115 P(x)=x15,x=1,2,3,4,5=0 other wise p(x=1or2)=p(x=1)+p(x=2)=115+215=15

If $p (x) = \frac{x}{15}, x = 1, 2, 3, 4, 5 = 0$ otherwise, then $p (x = 1 o r 2)$ is

The correct option is A $\frac{1}{15}$
$\begin{matrix} P (x) = \frac{x}{15}, x = 1, 2, 3, 4, 5 = 0 other wise \begin{matrix} p (x = 1 or 2) & = p (x = 1) + p (x = 2) = \frac{1}{15} + \frac{2}{15} = \frac{1}{5} \end{matrix} \end{matrix}$