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Question

If p(x) is a cubic polynomial with p(1) = 3, p(0) = 2 and p (–1) = 4, then 11p(x)dx is

A
2
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B
3
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C
4
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D
5
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Solution

The correct option is D 5
p(x)=ax3+bx2+cx+d
p(0) = 2
d = 2
p(1) = 3
a + b + c + 2 = 3
a + b + c = 1 …………… (1)
p(-1) = 4
-a +b - c +2 =4
-a +b -c =2
from(1)and (2)
2b=3b=32P(x)=ax3+32x2+cx+211p(x)dx=11(ax2+32x2+cx+2)dx=5

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