You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

And

If p: x is od...

Question

If $p : x$ is odd; $q : x^{2}$ is odd. Then " $x$ is odd and $x^{2}$ is not odd", is represented as

p \lor q

No worries! We‘ve got your back. Try BYJU‘S free classes today!

p \land q

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(\sim p) \lor q

No worries! We‘ve got your back. Try BYJU‘S free classes today!

p \land (\sim q)

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $p \land (\sim q)$
" $x$ is odd and $x^{2}$ is not odd", this sentence is conjunction of $p$ and negation of $q$ , therefore it is represented as $p \land (\sim q)$

Suggest Corrections

Similar questions

p : x

is odd,

q : x^{2}

is odd, then the symbolic form of "If

x

is not odd then

x^{2}

is odd", is

p : x

is odd,

q : x^{2}

is odd, then the symbolic form of "

x

is odd and

x^{2}

is not odd", is

Q. If

p : x

is odd ;

q : x^{2}

is odd, then "

x

is odd and

x^{2}

is not odd" is represented as

Q. Assertion :The contrapositive and converse of the statement: "If

x

is a prime number, then

x

is odd" are:
Contrapositive: "If

x

is not odd, then

x

is not a prime number.
Converse: If

x

is odd, then

x

is a prime number. Reason: If statement

p

implies

q

, then its contrapositive is

\sim q

implies

\sim p

, and its converse is

q

implies

p

Q. If

p and q

are substatements "A natural number is odd " and "A natural number is not divisible by

2

"respectively, then the biconditional statement

p \Leftrightarrow q

Join BYJU'S Learning Program

Explore more

And

Standard XII Mathematics

Join BYJU'S Learning Program

If p:x is odd; q:x2 is odd. Then "x is odd and x2 is not odd", is represented as

The correct option is D p∧(∼q)"x is odd and x2 is not odd", this sentence is conjunction of p and negation of q, therefore it is represented as p∧(∼q)

If $p : x$ is odd; $q : x^{2}$ is odd. Then " $x$ is odd and $x^{2}$ is not odd", is represented as

The correct option is D $p \land (\sim q)$
" $x$ is odd and $x^{2}$ is not odd", this sentence is conjunction of $p$ and negation of $q$ , therefore it is represented as $p \land (\sim q)$