If px-x2-2-2x-1- Then find the value of p2-2-

p(x)=x^2 2√(2)x+1 p(2√(2))=(2√(2))^2 2√(2)(2√(2))+1 =(2√(2))^2 (2√(2))^2+1 =0+1 =1 . ...

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Algebraic Identities

If px=x2-2√...

Question

If $p (x) = x^{2} - 2 \sqrt{2} x + 1$ . Then find the value of $p (2 \sqrt{2})$ .

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Solution

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If p(x)=x²-2√2x+1then find p(2√2)

If $p (x) = x^{2} - 2 \sqrt{2} x + 1$ , then $p (2 \sqrt{2})$ is equal to

If $p (x) = x^{2} - 2 \sqrt{2} x + 1$ then $p (2 \sqrt{2}) = ?$
(a) $0$
(b) $1$
(c) $4 \sqrt{2}$
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If p(x) = x² - 2*√2x + 1

Find p(2√2)

If $p (x) = x^{2} - 2 \sqrt{2} x + 1$ , then $p (2 \sqrt{2})$ is equal to

A) $0$
B) $1$
C) $4 \sqrt{2}$
D) $8 \sqrt{2} + 1$

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