If px-x2-2-2x-1 then p2-2- a 0 b 1 c 4-2 d -1

(b) 1 p(x)=x^2 2√(2)x+1 ∴ p (2 √(2)) =( 2 √(2))^2 2√(2)×2√2+1 = 8 8 + 1 = 1 ...

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Polynomials

If px=x2-2√2x...

Question

If $p (x) = x^{2} - 2 \sqrt{2} x + 1$ then $p (2 \sqrt{2}) = ?$
(a) $0$
(b) $1$
(c) $4 \sqrt{2}$
(d) $- 1$

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p (x) = x^{2} - 2 \sqrt{2} x + 1

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