If px - x2 - 3-3x-1- then the value of p3-3 is -

Given,p(x) = x^2 3√(3)x+1 x = nbsp;3√(3) p(3√(3)) = nbsp;(3√(3))^2 3√(3)(3√(3)) nbsp;+ 1 p(3√(3))= 27 27 + 1 p(3√(3)) nbsp;= 0 + 1 = 1 Thus, th ...

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If px = x2 - ...

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If $p (x) = x^{2} - 3 \sqrt{3} x + 1$ , then the value of $p (3 \sqrt{3})$ is .

\sqrt{3}

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3 \sqrt{3}

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If $p (x) = x^{2} - 3 \sqrt{3} x + 1$ , then the value of $p (3 \sqrt{3})$ is 0.

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p (x) = x^{2} - 5 x - 6,

p (1), p (2), p (3), p (0), p (- 1), p (- 2), p (- 3)

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