If p x - x 2-3 -3 x -1- then the value of p 3 -3 is 0A- 0 B- 3 -3

The correct option is B 3√3 Substituting 3√(3) for x in p(x), we get (3√(3))^2 3√(3)(3√(3)) + 1 = 27 27 + 1 = 0 + 1 = 1 Thus, the given statement is false ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VIII

Mathematics

Expansion of (x^2 - y^2)

If p x = x 2-...

Question

If p(x) = $x^{2} - 3 \sqrt{3} x + 1$ , then the value of $p (3 \sqrt{3})$ is 0.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3√3

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is B
3√3

Substituting $3 \sqrt{3}$ for x in p(x), we get

$(3 \sqrt{3})^{2}$ - $3 \sqrt{3}$ $(3 \sqrt{3}) + 1$

= 27 -27 + 1

= 0 + 1

= 1

Thus, the given statement is false.

Suggest Corrections

Similar questions

If p(x) = $x^{2} - 3 \sqrt{3} x + 1$ then the value of $p (3 \sqrt{3})$ is 0.

If $p (x) = x^{2} - 3 \sqrt{3} x + 1$ , then the value of $p (3 \sqrt{3})$ is 0.

if p(x) = $x^{2} - 3 \sqrt{3} x + 1$ then the value of $p (3 \sqrt{3})$ is 0.

Q. If

p (x) = \sqrt{x^{2} - 4 x + 3} + \sqrt{x^{2} - 9} - \sqrt{4 x^{2} - 14 x + 6}

then p(3) is

Q. If

p (x) = x^{2} - 5 x - 6,

then find the values of

p (1), p (2), p (3), p (0), p (- 1), p (- 2), p (- 3)

Join BYJU'S Learning Program

If p(x) = x2−3√3x+1, then the value of p(3√3) is 0.

The correct option is B 3√3 Substituting 3√3 for x in p(x), we get (3√3)2 - 3√3(3√3)+1 = 27 -27 + 1 = 0 + 1 = 1 Thus, the given statement is false.

If p(x) = $x^{2} - 3 \sqrt{3} x + 1$ , then the value of $p (3 \sqrt{3})$ is 0.

The correct option is B
3√3

Substituting $3 \sqrt{3}$ for x in p(x), we get

$(3 \sqrt{3})^{2}$ - $3 \sqrt{3}$ $(3 \sqrt{3}) + 1$

= 27 -27 + 1

= 0 + 1

= 1

Thus, the given statement is false.