Question

If $p\left(x\right)=x^2-4x+3,$. Evaluate $p\left(2\right)-p(-1)+p\left(\frac{1}{2}\right)$.

• A. $\frac{-5}{4}$
• B. $\frac{5}{4}$
• C. $\frac{-31}{4}$
• D. $\frac{31}{4}$

Answer 1

The correct option is C $\frac{-31}{4}$

After putting $x=2$ in equation, we get $-1$.
After putting $x=-1$, we get $8$
After putting $x=\frac{1}{2}$, we get $\frac{5}{4}$
So, $p\left(2\right)-p(-1)+p\left(\frac{1}{2}\right)=-1-8+\frac{5}{4}$

$=-9+\frac{5}{4}=\frac{-36+5}{4}=\frac{-31}{4}$