If $p (x) = x^{2} - 5 x - 6,$ then find the values of $p (1), p (2), p (3), p (0), p (- 1), p (- 2), p (- 3)$

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Solution

The polynomial
$p (x) = x^{2} - 5 x - 6$
$p (1) = 1^{2} - 5 (1) - 6 = 1 - 5 - 6 = - 10$
$p (2) = 2^{2} - 5 (2) - 6 = 4 - 10 - 6 = - 12$
$p (3) = 3^{2} - 5 (3) - 6 = 9 - 15 - 6 = - 12$
$p (0) = 0^{2} - 5 (0) - 6 = 0 - 0 - 6 = - 6$
$p (- 1) = (- 1)^{2} - 5 (- 1) - 6 = 1 + 5 - 6 = 0$
$p (- 2) = (- 2)^{2} - 5 (- 2) - 6 = 4 + 10 - 6 = 8$
$p (- 3) = (- 3)^{2} - 5 (- 3) - 6 = 9 + 15 - 6 = 18$

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