CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Range, Domain and Codomain

If p(x) = – x...

Question

If p(x) = – x 2 + px – p – 8 and p(x) < 0 for all real values of x, then the value of p cannot be

Open in App

Solution

Suggest Corrections

thumbs-up

0

Similar questions

p (x) = - x^{2} + px - p - 8 and p (x) < 0

for all real values of x, then the value of p cannot be

Q. Prove that the equation

x^{2} + p x - 1 = 0

has real and distinct roots for all real values of

p

Q. P(x) is a polynominal satisfying

P (x + \frac{3}{2}) = P (x)

, for all real values of x. If P(5) = 2002, then P(8) equals ..

Show that the roots of the equation $x^{2} + p x - q^{2} = 0$ are real for all real values of p and q

If $p (x) = x + 3$ , then find the value of $p (x) + p (- x)$

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Range, Domain and Codomain

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Range, Domain and Codomain

Standard X Mathematics

Join BYJU'S Learning Program

CrossIcon