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B
3
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C
5
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D
8
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Solution
The correct option is A0 Let f(x)=x3−4x2+5x−2 Now, f(2)=23−4×22+5×2−2 =8−16+10−2=0 Since, f(2)=0. Then we can say that, 2 is a zero of f(x)=x3−4x2+5x−2.