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Zeroes of a Polynomial

If px = x +...

Question

If $p (x) = x + 3$ , then $p (3) + p (- 3)$ , is equal to

A

3

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B

2

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C

0

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D

6

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Solution

The correct option is D $6$
$p (x) = x + 3$

For $x = 3$ , we get
$p (3) = 3 + 3 = 6$
For $x = - 3$
$p (- 3) = - 3 + 3 = 0$
So,
$p (3) + p (- 3) = 6 + 0 = 6$

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Similar questions

p = x^{\frac{1}{3}} + x^{\frac{- 1}{3}}

p^{3} - 3 p

p (x) = x^{2} - 5 x - 6,

then find the values of

p (1), p (2), p (3), p (0), p (- 1), p (- 2), p (- 3)

p (x) = 2 x + 3

P (1), P (3), P (- 3)

P (- 1)

p (x) = x + 3

p (x) + p (- x)

p (x)

is a polynomial of degree

3

p (0) = 4

p^{^{'}} (0) = 3, p^{^{''}} (0) = 6, p^{^{'''}} (x) = 6

p^{^{''}} (- 1) =

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