If px-x2-2 -2 x-1 then find p2 -2

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Scalar Triple Product

If px=x2-2 √2...

Question

If p(x)=x²-2√2x+1then find p(2√2)

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p (x) = x^{2} - 2 \sqrt{2} x + 1

p (2 \sqrt{2})

If $p (x) = x^{2} - 2 \sqrt{2} x + 1$ , then $p (2 \sqrt{2})$ is equal to

If p(x) = x² - 2*√2x + 1

Find p(2√2)

If $p (x) = x^{2} - 2 \sqrt{2} x + 1$ then $p (2 \sqrt{2}) = ?$
(a) $0$
(b) $1$
(c) $4 \sqrt{2}$
(d) $- 1$

If $p (x) = x^{2} - 2 \sqrt{2} x + 1$ , then $p (2 \sqrt{2})$ is equal to

A) $0$
B) $1$
C) $4 \sqrt{2}$
D) $8 \sqrt{2} + 1$

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