The correct options are
A Distance of P from (3,0) is always constant.
D x2+y2−6x−7=0
By section formula,
(x,y)=(20cosθ+155,20sinθ+05)
=(4cosθ+3,4sinθ)
⇒x=4cosθ+3,y=4sinθ
Since, cosθ and sinθ∈[−1,1]
⇒x∈[−1,7] and y∈[−4,4]
Distance of P from (3,0) is √(x−3)2+y2 =√16sin2θ+16cos2θ=4, which is a constant.
⇒(x−3)2+y2=42
⇒x2+y2−6x−7=0