If P x, y is any point on the line joining the points A a,0 and B b,0 show that xa+yb=1.
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Solution
Given that P(x,y) be any point on the straight line AB cuts off intercepts a and b on x-axis at A(a,0) and y-axis at B(0,b) . ∴ Slope of the straight line AB=−ba Then the equation of straight line by the slope - intercept form y=(−bax+b) ⇒yb=(−1ax+1) ⇒xa+yb=1.