If PA and PB are tangents from an outside point P such that PA = 10 cm and ∠APB = 60°. Find the length of chord AB.
PA and PB are the tangents from a point P outside the circle.
PA = 10 cm and ∠APB = 60°
Tangents drawn from a point outside the circle are equal.
PA = PB = 10 cm
∠PAB = ∠PBA
(Angles opposite to equal sides)
In ∆APB,
∠APB + ∠PAB + ∠PBA = 180° (Sum of angles of a triangle)
=> 60° + ∠PAB + ∠PAB = 180°
=> 2 ∠PAB = 180° – 60° = 120°
∠PAB = 60°
∠PBA = ∠PAB = 60°
So, ∆APB is an equilateral triangle.
PA = PB = AB = 10 cm
Hence, length of chord AB = 10 cm