Question

If PA and PB are two tangents to a circle with centre O such that $\angle$ APB = ${80}^o$. Then, $\angle$ AOP = ?

(a) ${40}^o$ (b) ${50}^o$ (c) ${60}^o$ (d) ${70}^o$

Answer 1

Correct Answer:
(B) 50° Description for Correct answer

∠AOB=360−(90+90)−80


∠AOB=180−80=100

then. ∠AOP=100/2=50