Question

If PA and PB are two tangents to a circle with centre O such that $\angle$ AOB = ${110}^o$ then $\angle$ APB is equal to

(a) ${55}^o$ (b) ${60}^o$ (c) ${70}^o$ (d) ${90}^o$

Answer 1

∠ AOB = 110o then ∠APB is equal to
∠ AOB+∠APB=180
∠APB=180-110=70