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Question

If PCl5 is 80% dissociated at 523 K, what is the vapour density of the equilibrium mixture at 523 K ?

A
57.92
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B
72.93
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C
45.45
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D
67.92
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Solution

The correct option is A 57.92
PCl5(g)PCl3(g)+Cl2(g)
α (Degree of dissociation)=80%=80100=0.8
Theoretical vapour/Normal vapour density,
D=Normal molar mass2=208.52=104.25

Vapour density of the equilibrium mixture, d=?
We have the relation,
α=Dd(n1)d

0.8=104.25d(21)d
0.8 d=104.25d
0.8 d+d=104.25
1.8 d=104.25
d=104.251.8=57.92

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