Question

If $P\left(E\right)=0.05$, what is the probability of ‘not $E$’?

Answer 1

Compute the required probability:

It is given that, $P\left(E\right)=0.05$

The probability of not happening an event is equal to $1$ minus the probability of happening an event.

That is

$P\left(E\right)+P(notE)=1$

$\Rightarrow$ $P(notE)=1-P\left(E\right)$

$\Rightarrow$ $P(notE)=1-0.05$

$\Rightarrow$ $P(notE)=0.95$

Hence the probability of ‘not $E$’ is $0.95$.