Question

If perimeter of a triangle $ABC$ with sides $3$ cm, $4$ cm and $5$ cm is two times the perimeter of a square then find area of the square.

• A. $\frac{3}{2}$
• B. $\frac{5}{2}$
• C. $\frac{9}{4}$
• D. $\frac{14}{4}$

Answer 1

The correct option is C $\frac{9}{4}$

Perimeter of triangle $=3+4+5$$=12$cm

perimeter of square $=$ Perimeter of triangle$/2$

perimeter of square $=$$6$cm

Side of square $=$$\frac{3}{2}$

Area of square $=$$\frac{9}{4}$

Hence, Option C is correct.